Beam Lux
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Lux, candela, and beam diameter

Example 1000 lm, 36 degrees, 2 m

Worked inputs. Not a lamp row.

Worked example

beam angle 36°distance 2 mbeam diameter

Illuminance812.9527 lx

E_lux = I / d^2

Beam diameter1.2997 m

D = 2 × d × tan(theta / 2)

These formulas assume the flux is spread evenly inside the cone. A real lamp does not have that ideal distribution.

Solid angle, candela, and throw

Solid angle 0.3075 sr

Omega = 2 × pi × (1 - cos(theta / 2))

Luminous intensity 3251.8107 cd

I = Phi / Omega

Foot-candles 75.5251 fc

E_fc = E_lux / 10.764

Throw to 0.25 lux 114.0493 m

d_throw = 2 × sqrt(I)

Notes only: hallways and stairs 100 lux; office and classroom 300 to 500; drafting 750 to 1000; operating theater 10000 to 50000.

Theta is converted from degrees to radians for cos and tan. The feet form is not applied as a second conversion.